While implementing a macro I wanted to play nice for the user and show lineinfo() in case of parsing error, since parseExpr was pointing to the line of the macro rather than the callsite line. I wrapped parseExpr in a try/except but when I removed the failing code the except was still being run. See this example too:
import macros
macro rambo(text: string): expr =
result = newLit("'" & text.strVal & "'")
macro ghost(text: string): expr =
try:
result = newLit("ok ")
except:
result = newLit("wat ")
const
a = "something "
b = ghost("ghostly ")
c = rambo("stallone")
echo a, b, c