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4671 :: Convert string to char

• greenfork (orginal) [2019-02-21T15:38:04+01:00] view original

  var
    s1: string = "a"
    s2: string = r"\n"
    c1: char
    c2: char
  
  c1 = @s1[0]
  c2 = ???
  Run

  How do I convert the string r"\n" to its char representation '\n'?

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• Stefan_Salewski (orginal) [2019-02-21T16:16:59+01:00] view original

  Your desire not really makes sense. Preceding the string with r requests a raw string, so r"n" is the two letters and n, not a newline. Use plain "n" when you want that the escape sequences is interpreted. "n"[0] is than that newline char.

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• greenfork (orginal) [2019-02-21T17:02:57+01:00] view original

  I may have worded it incorrectly. I want to convert the string of 2 consecutive characters to a single char which would consist of these same 2 characters. It's like a char composition: I get 2 characters, glue them together and see if they can represent a single char.

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• Araq (orginal) [2019-02-21T17:25:02+01:00] view original

  Not sure but take a look at unicode module.

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• cdome (orginal) [2019-02-21T17:30:31+01:00] view original

  'L' is the closest you can get

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• mashingan (orginal) [2019-02-21T17:35:19+01:00] view original

  You can't generically represent string as char, but for your specific case, you can do it like this:

  import options
  
  proc chr(s: string): Option[char] =
    if s == "\\n": some('\n')
    else: none(char)
  
  let nlinerepr = r"\\n".chr
  if nlinerepr.isSome:
     echo nlinerepr.some
  let otherstr = "hello".chr
  if otherstr.isNone:
     echo "no char repr"
  Run

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• juancarlospaco (orginal) [2019-02-21T19:56:08+01:00] view original

  Use the int ?. assert char(10) == '\n'

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