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9052 :: confusing behavior do to overloading of and for binary and, as well as logical and.

• solomonthewise (orginal) [2022-03-28T03:04:26+02:00] view original

  top_row and (b.mask + (1 shl (7 * row))) == 0 gives a error while (top_row and (b.mask + (1 shl (7 * row)))) == 0 gives the result I want. notice that b.mask is a int64 and so is top_row. I think I know why this occurs. since with the brackets and becomes binary and, then without the brackets it becomes a logical and. Is this intended behavior?

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• sls1005 (orginal) [2022-03-28T04:37:25+02:00] view original

  The priority of == is highter than and, therefore "a and b == 0" means "(a) and (b == 0)" while (a and b) == 0 does what you expect.

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• DeletedUser (orginal) [2022-03-28T06:54:42+02:00] view original

  It's to support a == b and c == d.

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