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6861 :: get raw command line

• sflennik (orginal) [2020-09-26T05:13:19+02:00] view original

  Is there a way to get the command line string before it's parsed? The commandLineParams proc almost works but it removes the quotes.

  
  import os
  import strutils
  echo commandLineParams().join(" ")
  
  $ bin/tests/t -l=asdf --filename="file name with spaces"
  -l=asdf --filename=file name with spaces
  Run

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• cdunn2001 (orginal) [2020-09-26T06:34:16+02:00] view original

  It doesn't exactly "remove" the quotes. The shell interprets them and stores into command-line arguments without them. A C program works the same way.

  I think you want shellQuote.

  https://nim-lang.org/docs/os.html#quoteShell%2Cstring

  import os
  import strutils
  import sugar
  #echo commandLineParams().join(" ")
  proc main() =
    let cl = sugar.collect(newSeq):
      for p in commandLineParams():
        os.quoteShell(p)
    
    echo cl.join(" ")
  
  main()
  Run

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• cdunn2001 (orginal) [2020-09-26T06:36:55+02:00] view original

  Result:

  
  $ ./foo 1 "2 3" 4
  1 '2 3' 4
  Run

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• sflennik (orginal) [2020-09-26T23:52:42+02:00] view original

  Thanks for pointing out that the shell is responsible for quote handling. I was thinking there was of some general function like the windows GetCommandLine. I want to log the original string so I know what the user entered. I've decided that "echo $commandLineParams()" works for me.

  I need to study up on the sugar stuff, looks powerful.

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