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3727 :: Can I do this in Nim?

• jzakiya (orginal) [2018-04-05T03:56:08+02:00] view original

  I have this code where I'm setting all the bytes in seg to 0.

  
  for b in s_row..s_row+KB-1: seg[b] = 0
  Run

  Can I do something like: seg[a..b] = 0

  Then I have this code that counts all the 0 in seg

  
  for k in 0..Kn-1: (if seg[s_row+k] == 0: sum += 1)
  Run

  Is there a way to do something like this: sum = seg[a..b].count(0)

  If so, would they be faster than the current code constructs?

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• mashingan (orginal) [2018-04-05T06:16:34+02:00] view original

  use fill proc, https://nim-lang.org/docs/algorithm.html#fill,openArray[T],Natural,Natural,T

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• miran (orginal) [2018-04-05T08:35:53+02:00] view original

  ...and there is count in sequtils: https://nim-lang.org/docs/sequtils.html#count,openArray[T],T

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