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1764 :: Is socket.connect("192.168.0.123", Port(8000)) right ?

• e2718e (orginal) [2015-11-03T16:55:28+01:00] view original

  import net

  var data:array[0..87,int8]

  var s = newSocket()

  s.connect("192.168.0.123", Port(8000), 5000) # Can't connect. And "192.168.0.123" is my ip.

  s.connect("localhost", Port(8000), 5000) # runs well.

  var r = s.send(addr(data), len(data))

  s.close()

  How do I write the connection function with a ip ?

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• OderWat (orginal) [2015-11-03T17:06:31+01:00] view original

  I would test if the server really listens on 192.168.0.123 ... did you check this (telnet 192.168.0.123 8000)?

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• e2718e (orginal) [2015-11-03T17:12:34+01:00] view original

  I have a server on 192.168.0.123 and 8000 port is listened by this server. It can run by using "localhost" on the "192.168.0.123" computer.

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• OderWat (orginal) [2015-11-03T17:35:37+01:00] view original

  Accessibility as "localhost" is not the same as the IP. Try 127.0.0.1 as IP in your code. I just checked that IPs work as you specify it.

  import net
  
  var s = newSocket()
  
  s.connect("173.194.112.119", Port(80), 5000)
  #s.connect("localhost", Port(80), 5000)
  s.send("GET / HTTP/1.0\nhost: www.google.de\n\n")
  
  var
     rc = ""
     r = s.recv(rc, 100_000)
  echo r
  echo rc
  
  s.close()
  Run

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• e2718e (orginal) [2015-11-03T17:55:19+01:00] view original

  Thanks for OderWat!

  I have closed all the firewall. And Python can't connect,too. But "127.0.0.1" can connect.

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